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Different solutions possible, or not? |
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I guess not3. Kxd5 Kf3 4. c4 g4 5. c5 g3 6. cxb6 g2 7. b7 g1=Q 8. b8=Q Then I tried playing with White using the same play as above, and the computer has 3. Kxd5 h5 4. c4 h4 5. c5 h3 6. cxb6 h2 7. b7 h1=Q+ 8. Kd6 Qxb7 So it looks like the solution is the best. |
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Thanks breakerofwind! |
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