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fratellowv 08-Nov-13, 06:34 » Report abuse |
Second the question |
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![]() 2.Be2 Qa4 3.Nxc7 Rxd1+ 4.Bxd1 Qxa2 5.Nxe6 fxe6 6.Qxe5+ Kc8 7.f7 |
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rich_sposato 04-Nov-14, 18:21 » Report abuse |
![]() 1. ... Bc7 2. Be2 Qa4 3. Nxc7 Rxd1+ 4. Bxd1 Qa3 5. Nxe6 fxe6 6. Qxe5+ Kc8 7. Qxe6+ Kc7 White soon promotes a pawn and wins when the second queen delivers checkmate. If the black queen takes the pawn on c3, this is the outcome. 1. ... Bc7 2. Be2 Qa4 3. Nxc7 Rxd1+ 4. Bxd1 Qa3 5. Nxe6 Qxc3+ 6. Qd2 Qxd2+ 7. Kxd2 fxe6 8. f7 Kc7 9. f8=Q Either way, white promotes and wins because black has nothing but pawns left. Black's best option is to lose the queen because black still has a rook, bishop, a knight, and six pawns. |
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gr00d 01-Oct-25, 15:50 » Report abuse |
![]() Nxc7 Kxc7 Qxe5+ Does eventually win material but it's too far in the future to realistically calculate in one of these puzzles. It makes the solution feels too positional for the spirit of the exercise when black sacrifices the queen to stop white from getting a pass pawn five or six moves down the line (especially with all the check threats from the queen that you have to deal with after that before you can actually promote). |
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